Discrete Probability Distribution Solutions
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Practicing material for Quiz #5 – Discrete Probability Distribution SOLUTIONS
1. The manager of a baseball team has determined that the number of walks, x, issued in a game by one of the pitchers is described by the probability distribution given below.
| x | p(x) |
|---|---|
| 0 | 0.05 |
| 1 | 0.10 |
| 2 | 0.15 |
| 3 | 0.45 |
| 4 | 0.15 |
| 5 | 0.10 |
- This pitcher issues as few as 0 walks and as many as 5 walks in a game.
- Determine the following probabilities
i. P(x = 2) = 0.15
ii. P(x > 4) = 1 – 0.10 = 0.90
iii. P(x > 5) = 0
iv. P(2 < x < 4) = 0.15+0.45+0.15 = 0.75
- Calculate the mean for this discrete probability distribution, µ = 2.85 walks
µ = Sxp(x) = 0(0.05) + 1(0.10) + 2(0.15) + 3(0.45) + 4(0.15) + 5(0.10) = 2.85
- The average, over time, of walks issued in a game by one of the pitchers is 2.