Mathematics Practice Solutions: Geometry and Mensuration
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Answer Key
- 1: A
- 2: C
- 3: 50°
- 4: B
- 5: D
- 6: C
- 7: C
- 8: C
- 9: A
- 10: A
11. Congruency Proof
Given: OA = OD and OB = OC.
In ΔOBC, since OB = OC, then ∠OBC = ∠OCB. Consequently, ∠OCD = ∠OBA.
In ΔOAD, since OA = OD, then ∠OAD = ∠ODA.
Since ∠OCD = ∠OBA and ∠OAD = ∠ODA, we find that ∠AOB in ΔOAB is equal to ∠COD in ΔOCD.
Conclusion: By SAS congruency, ΔOAB ≅ ΔOCD. Therefore, AB = CD.
12. Conical Cloth Calculation
Given: r = 7m, h = 24m.
l = √(r² + h²) = √(49 + 576) = √625 = 25m.
Curved Surface Area (CSA) = πrl = (22/7) × 7 × 25 = 550m².
Length of cloth = 550m² / 5m = 110m.
13. Sphere Diameter
Surface area of sphere = 154 cm².
4πr² = 154
r² = 154 / (4π) = (154 / 4) × (7 / 22) = 49 / 4.
r = √(49 / 4) = 7/2 = 3.5 cm.
Diameter (D)... Continue reading "Mathematics Practice Solutions: Geometry and Mensuration" »