Bernoulli's Equation and Energy Balance
Since the fluid is incompressible, A1Δx1 = A2Δx2 = ΔV.
Work–Energy Principle Derivation
The work done on the fluid is due to the pressure acting on it.
Therefore, the work done, ΔW = F1Δx1 - F2Δx2
= P1A1Δx1 - P2A2Δx2
= P1ΔV - P2ΔV
ΔW = (P1 - P2) ΔV
Change in kinetic energy, ΔKE = KE2 - KE1
= ½ mv22 - ½ mv12
ΔKE = ½ m (v22 - v12)
= ½ ρ ΔV (v22 - v12)
Change in potential energy, ΔPE = PE2 - PE1
= m g h2 - m g h1 = m g (h2 - h1)
Since m = ρ ΔV, ΔPE = ρ ΔV g (h2 - h1)
Using the work–energy principle,
ΔW = ΔKE + ΔPE
(P1 - P2) ΔV = ½ ρ ΔV (v22 - v12) + ρ ΔV g (h2 - h1)
Therefore, P1 - P2 = ½ ρ (v22 - v12) + ρ g (h2 - h1)
Rearranging
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