Thermodynamics Exam Cheat Sheet: Problem Solving Recipes

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Thermodynamics Exam Cheat Sheet: Problem-Solving Recipes


🔹 Problem 1: Property Changes & T-s Sketch

(HW 9 Q1–Q3)
1a. Ideal-Gas Entropy Change

Statement: Air (ideal gas) in a piston-cylinder goes from State 1: T₁ = 350 K, p₁ = 100 kPa to State 2: T₂ = 550 K, p₂ = 700 kPa. Find Δs (kJ/kg·K) (a) reversible, (b) with irreversibilities.

1b. Isothermal Water Compression

Statement: 1 kg water in a piston-cylinder, initially saturated vapor at T = 160 °C, p = 150 kPa, isothermally compressed to saturated liquid. Work on water W = -471.5 kJ. Find (a) Q (kJ), (b) ΔS (kJ/K). Sketch T-s.

Steps for 1a (Ideal Gas)

  1. Formula:

    RSNrrqki1Pdx0lxAQAkIgEQGRqhaGEBACQiBHBESqOYKpRwkBISAERKpaA0JACAiBHBEQqeYIph4lBISAEBCpag0IASEgBHJEQKSaI5h6lBAQAkJApKo1IASEgBDIEQGRao5g6lFCQAgIAZGq1oAQEAJCIEcERKo5gqlHCQEhIAREqloDQkAICIEcERCp5gimHiUEhIAQEKlqDQgBISAEckRApJojmHqUEBACQkCkqjUgBISAEMgRAZFqjmDqUUJACAgBkarWgBAQAkIgRwT+C4qwWLAXQ0ZhAAAAAElFTkSuQmCC
  2. Compute

    • gvOBsuyEZ5HqQAAAABJRU5ErkJggg==
  3. Evaluate

    mj8bC4AOAAAAAElFTkSuQmCC
  4. Irreversible:

    K31v5BwDCy1WAIdE8EjMy753u3WRsChoAhYAh0EAJG5h30Mm0qhoAhYAgYAt0TASPz7vnebdaGgCFgCBgCHYTAfwC3o+ReaddfmgAAAABJRU5ErkJggg==

Steps for 1b (Water Compression)

  1. 1st Law:

    wLL0pjOEW4aVQAAAABJRU5ErkJggg==
  2. Table Lookup at 160 °C (saturated):

    • raSjabA0l0JAAXcNppuqqyVAcqWarlVQCKoHCS0AB+v+XSAG68OqqA1QJqASaqwQUoJvryuu8VQIqgcJLQAG68EukA1QJqASaqwQUoJvryuu8VQIqgcJLQAG68EukA1QJqASaqwQUoJvryuu8VQIqgcJLQAG68EukA1QJqASaqwQUoJvryuu8VQIqgcJLQAG68EukA1QJqASaqwQUoJvryuu8VQIqgcJLQAG68EukA1QJqASaqwQUoJvryuu8VQIqgcJL4P8AvQotavveLd4AAAAASUVORK5CYII=
  3. Compute ΔU:

    jPpdT+lsChcCBeA7I53IIideVj54GmcgPBwLA5WctMh8JxRx8dy1tRWzmAwgE6zQH5FuBfLzT54xTnWZamHymHAgAlyk780WMcDC5rClTpqSuis3XDMJoajIHyP+RYzfvYKzJ8wljr3kcCABX89bMa8QksClkoeAj6kYFL2Khc+BASg4gb+Ta7cPuKR8P3QIHMuFAALhM2JhvIpT8UorMBcmhBQ6UmwNSjUkZeHV+hLbc8wz088+BAHD5X6MwwsCBwIHAgcCBIjjwPyHOpYhFvSY6AAAAAElFTkSuQmCC
  4. Compute Q:

    A41hMJ0QH2JLAAAAAElFTkSuQmCC
  5. Compute ΔS:

    m4Prhq1optRgPoVnxHac2JAokC1VPAp7Rn9bO6R0wAXQGlJaHMHsrnLmIF01c6BCEJigBwX5pYIbkElNEjXCF3vCudMA2WKJAokCjQRBQgVkz50DIlpavaTgLoqiiZxkkUSBRIFEgUaGkKSFIbxVti689XSYAE0FVSM42VKJAokCiQKNCyFCDxi9sIRaU9G7XBBNCNonSaJ1EgUSBRIFGgqSlAWU8yxkM+3lTPDSWArid109iJAokCiQKJAokCkRRIAB1JuPRYokCiQKJAokCiQD0p8H8TgFR8uQaowwAAAABJRU5ErkJggg==
  6. Sketch T-s: 93JBfWJ7VQRddpKSniyZbh6oIKAKKgCLQtxHgCBE+lirfraSGktOx2VhB7SL1m9riCCjpUelQBBQBRUARUAT6CALsCOOjxXL6P0X6FJRTCMz387RVI6CkRyVEEVAEFAFFQBFQBLoCASU9XTHNOkhFQBFQBBQBRUAR+D+qO+2s2IUaDgAAAABJRU5ErkJggg==


🔹 Problem 2: Single-Component Device Check

(HW 10 Q1–Q4 & HW 9 Q5–Q10)

Statement: Steady-flow device (turbine or compressor) with inlet (p₁,T₁) and outlet (p₂,T₂_meas). (a) Check feasibility via entropy generation (2nd Law). (b) Use energy balance (1st Law) to find W or Q. (c) Compute isentropic efficiency if asked.

Steps

  1. Sketch control volume with inlet 1 and outlet 2.

  2. 2nd Law Check:

    w8OYBsiagfaUwAAAABJRU5ErkJggg==
  3. Isentropic Efficiency:

    • wPQgv2RxMIJdwAAAABJRU5ErkJggg==
  4. 1st Law Steady-Flow:
    hQAAAABJRU5ErkJggg==

  5. Entropy Balance:
    wAAAABJRU5ErkJggg==

🔹 Problem 3: Carnot Cycle Analysis

(HW 8 – All Q’s)

Statement: Analyze a Carnot cycle (power, refrigerator, or heat pump) between temperatures T_H and T_C:

  • Two isothermals (T_H, T_C)
  • Two isentropics

Steps

  1. Draw p-v and T-s (or T-v) loops, label states 1→4.

  2. List Processes:

    1. Isothermal @ T_H (q_in or q_out)
    2. Adiabatic (isentropic)
    3. Isothermal @ T_C (q_out or q_in)
    4. Adiabatic (isentropic)
  3. Compute Each Leg:

    • Isothermal: q=TΔs=h_end-h_start
    • Adiabatic: w=h_start-h_end with s constant.
  4. Net Work/Heat: w_net=q_in-q_out.

  5. Efficiency/COP:

    η=1-(T_C/T_H), COP_ref=T_C/(T_H-T_C), COP_hp=T_H/(T_H-T_C).

🔹 Problem 4: Integrated Multi-Component Cycle

(HW 10 Q5–Q9 & HW 7 Q4–Q5)

Statement: Full Rankine or combined-cycle plant: boiler → turbine(s) → condenser → pump(s) → reheater/heat exchanger. Find net power, η_th, component η’s, cooling-water flow, entropy generation.

Steps

  1. Sketch full plant, label all states.

  2. State Table: p, T, h, s, x.

  3. Turbine/Nozzle:

    w_t=h_in-h_out,act, η_t=(h_in-h_out,act)/(h_in-h_out,s)
  4. Pump/Compressor:

    w_p=h_out,act-h_in, η_p=(h_out,s-h_in)/(h_out,act-h_in)
    with w_p,s ≈ v(P_out-P_in).
  5. Heat Duties:
    q_in=h_boiler,out-h_boiler,in, q_out=h_cond,in-h_cond,out

  6. Net Work & Efficiency:
    w_net=∑w_t-∑w_p, η_th=w_net/q_in

  7. Cooling-Water Flow:
    ṁ_w=Q_out/(c_p,w(T_w,out-T_w,in))

  8. Entropy-Generation:
    Ṡ_gen=∑ṁ(s_out-s_in)+∑(Q/T_b)≥0


Use this sheet verbatim. Each problem includes its statement, source, and a numbered recipe—only algebra and table lookups remain. Good luck!

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