Calculus Derivative Solutions and Function Analysis
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Derivatives of Algebraic and Transcendental Functions
- f(x) = (x3 - 3x)3: f'(x) = 3(x3 - 3x)2 · (3x2 - 3) = 9x8 - 63x6 + 135x4 - 81x2
- f(x) = 2ex · (3x - 1): f'(x) = 2ex · (3x - 1) + 2ex · 3 = 6xex - 2ex + 6ex = 6xex + 4ex
- f(x) = ln(x2 + 6x): f'(x) = (1 / (x2 + 6x)) · (2x + 6)
- f(x) = 1 / ln x: f'(x) = -1(ln x)-2 · (1 / x) = -1 / (x ln2 x)
- f(x) = 2 cos x · sin x: f'(x) = 2(-sin x) · sin x + 2 cos x · cos x = 2(cos2 x - sin2 x)
- f(x) = 2x2 - 3: f'(x) = 2x2 - 3 · 2x · ln 2
- f(x) = cos3(2x): f'(x) = 3 · (cos 2x)2 · (-sin 2x) · 2 = -6 cos2(2x) · sin(2x)
- f(x) = (2x3 - 3x) / (x2 - 1): f'(x) = [(6x2 - 3)(x2 - 1) - (2x3 - 3x)(2x)] / (x2 - 1)2
- f(x) = (x2 - 1) / (x + 1): f'(x) = [(2x)(x + 1) - (x2 - 1) · 1] / (x + 1)2
- f(x) = ex2 / (1 - ex): f'(x) =