Physics Mechanics: Kinematics and Forces Principles
Kinematics: Understanding Motion
Scalars and Vectors in Motion
Scalars: Quantities possessing magnitude only (e.g., speed, distance, time, mass).
Vectors: Quantities possessing both magnitude and direction (e.g., velocity, displacement, acceleration, force). These are represented by arrows.
Position: Displacement (Vector)
Change: Distance (Scalar), Displacement (Vector)
Rate: Speed (Scalar), Velocity (Vector)
Change in Rate: Acceleration (Vector)
Constant Acceleration Equations
Variables Used: Final velocity (v), Initial velocity (u), Acceleration (a), Displacement (s), Time (t).
Key Equations:
v = u + at
v² = u² + 2as
s = ½(u+v)t
s = ut + ½at²
s = vt - ½at²
Graphing Motion Characteristics
Displacement-Time (s-t) Graph:
A flat line indicates the object is stationary.
The gradient represents the velocity.
Velocity-Time (v-t) Graph:
A flat line signifies constant velocity.
The gradient represents the acceleration.
The area under the graph represents the displacement.
Acceleration-Time (a-t) Graph:
A flat line shows constant acceleration.
The area under the graph represents the change in velocity.
Forces and Motion Dynamics
Newton's Laws of Motion
First Law: An object's velocity remains constant unless acted upon by a net external force.
Second Law: The net force equals mass times acceleration (Fnet = ma).
Third Law: For every action, there is an equal and opposite reaction (Fon A by B = -Fon B by A).
Common Types of Forces
Gravity (Fg): Calculated as Fg = mg, where g ≈ 9.8 N kg-1.
Normal Force (FN): Acts perpendicular to the surface contact.
Friction (Ff): A force that actively resists motion between surfaces.
Force Vectors in Two Dimensions (2D)
Components: Fx = F cos(θ), Fy = F sin(θ).
Net Force Calculation:
Magnitude: F = √(Fx² + Fy²)
Angle: θ = tan-1(Fy/Fx)
Forces on Inclined Planes
Gravity Components (Relative to the slope):
Perpendicular to slope: FN = mg cos(θ)
Parallel to slope (frictionless): Fnet = mg sin(θ)
With Friction: Fnet = mg sin(θ) - Ff.
Example: Skier on a Frictionless Slope
Problem: A skier (mass m=90 kg) is on a frictionless slope inclined at θ=35°. Determine the resulting acceleration (a).
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