Notes, summaries, assignments, exams, and exercises for Computer science for Baccalaureate

Race Conditions in JK Flip-Flops

What is a race condition in a JK flip-flop and how can it be overcome?

In a JK flip-flop, a race condition occurs when both J and K inputs are high (1) while the clock pulse is active. This leads to unpredictable behavior, where the output state toggles rapidly and does not settle to a stable value because the propagation delay is shorter than the clock pulse width.

To overcome this, you can use clocked JK flip-flops or edge-triggered designs. This ensures that inputs are only processed during a specific clock edge, making the output stable and effectively avoiding race conditions.

Master-Slave JK Flip-Flop Configuration

Explain the master-slave flip-flop using a JK flip-flop with logic circuits, truth tables, and

Number Pyramid of Integers

Write a program to generate the following patterns of integers:

              1
            121
           12321
         1234321

Corrected C Program (Number Pyramid)

The following C program prints the above centered palindrome number pyramid. It prompts for the number of rows.

#include <stdio.h>

int main()
{
    int i, j, row;
    printf("Enter number of rows: ");
    if (scanf("%d", &row) != 1) {
        printf("Invalid input.\n");
        return 1;
    }

    for (i = 1; i <= row; i++)
    {
        for (j = 1; j <= row - i; j++)
        {
            printf(" ");
        }
        for (j = 1; j <= i; j++)
        {
            printf("%d", j);
        }
        for (j = i - 1; j >= 1; j--)

WEEK 1: Software that Manages Computer Hardware

Operating System as an Abstract Machine, Service Provider, and Resource Manager. OS Objectives: Convenience, Efficiency, and Ability to Evolve.

Performance Indices

Arrival Time, Service Time, Turnaround Time, Normalized Turnaround Time. First-Come-First-Served (FCFS) Scheduling Policy.

Microprocessor and DMA Activity

Impact of Microprocessor Bus Configuration and DMA Activity on System Speed.

Memory System and Cache

Cache and Main Memory Access Time, Average Access Time Calculation.

iOS and Android

Similarities and Differences between iOS and Android.

Job Execution and CPU Utilization

CPU Utilization for Uniprogramming and Multiprogramming.

Direct Memory Access (DMA)

Coordination, Memory Operations Completion,...

1. Speed

Computers process data at an extremely fast rate. In a few seconds, they can perform tasks that would take a human days or even years to complete. Computer speed is measured in MHz (Megahertz) or GHz (Gigahertz).

• Microcomputers: Execute millions of instructions per second consistently without error.
• Supercomputers: Operate at speeds measured in nanoseconds and picoseconds, performing tasks one thousand to one million times faster than microcomputers.

2. Accuracy

Computers are highly accurate, though performance depends on the instructions provided. Because computers only execute what they are programmed to do, faulty instructions lead to faulty results—a concept known as GIGO (Garbage In, Garbage Out).

While errors can occur, advanced...

Understanding Parsers and Abstract Syntax

A Parser is a program that translates terms in concrete syntax into abstract syntax.

• In our language (PLAI, not Racket), we use {braces} instead of (parentheses) to distinguish concrete syntax from Scheme by looking at the delimiters.
• The parser identifies the program structure and converts it to the appropriate abstract syntax. This requires a clear specification of the concrete syntax using Backus-Naur Form (BNF).

Arithmetic BNF Specification

<AE> ::= <num>
      | {+ <AE> <AE>}
      | {- <AE> <AE>}

• The <AE> in BNF is a non-terminal, meaning it can be rewritten as one of the items on the right-hand side.
• The ::= symbol means “can be rewritten as.”
• Each | presents

TCP/IP Layering: Advantages and Drawbacks

Layering decomposes the overall communications problem into a number of more manageable sub-problems. Perhaps the major disadvantage is the processing and data overhead.

• Processing Overhead: As many as seven modules (OSI model) are invoked to move data from the application through the communications software.
• Data Overhead: This results from appending multiple headers to the data.

Another possible disadvantage is that there must be at least one protocol standard per layer. With so many layers, it takes a long time to develop and promulgate the standards.

Layering Overhead Calculation Example

A transport-layer message consisting of 2100 bits of data and 250 bits of header is sent to a network layer, which...

Tree Traversal Methods

Preorder traversal: Visit the root, visit the left subtree, and then visit the right subtree.

Inorder traversal: Visit the left subtree, visit the root, and then visit the right subtree.

Postorder traversal: Visit the left subtree, visit the right subtree, and then visit the root.

Breadth-First Traversal: Visit the root, visit the children of the root (left to right), and then the children of the children (left to right), going down level by level.

Depth-First Traversal: Rather than visiting the tree level-by-level like in breadth-first traversal, visit the root, go all the way down the left on one path, and then move across the tree to the right, going down all the paths until the end.

Hashing and Collision Resolution

Hashing:

THE FILE: A file is a set of ordered documents that are related by some circumstance or event. It is essential for a company to have a file that is to sort and classify documentation in a particular way.

Why: It allows to keep, store and safeguard information, It can be easily and quickly found, To comply with the law, It can help in the decision-making process

Types of files:

1) Active: documents that are currently being used and queried

2) Semi-active: documents no longer effective but kept for legal reasons

3) Inactive: documents not valid but with a historical or documentary value

The File system: is the criterion used for ordering information.

• Alphabetical: Information classified in the order of the alphabet *

• Numerical: information in which each

Data Structure (Syllabus)

Semester & Branch: 3rd sem CSE/IT Teachers Assessment : 10 Marks
Theory: 4 Periods per Week Class Test : 20 Marks
Total Periods: 60 Periods per Semester End Semester Exam : 70 Marks
Examination: 3 Hours TOTAL MARKS : 100 Marks

Objective :

The effectiveness of implementation of any application in computer mainly depends on the that how effectively its information can be stored in the computer. For this purpose various -structures are used. This paper will expose the students to various fundamentals structures arrays, stacks, queues, trees etc. It will also expose the students to some fundamental, I/0 manipulation techniques like sorting, searching etc

1.0 INTRODUCTION: 04

• 1.1 Explain Data, Information, data types
• 1.2 Define

Introduction to Architecture

• Instruction Set Architecture (ISA): An assembly language programmer's view of the microprocessor.
• Assembler: Translates symbolic assembly language code into binary machine language code.

Computer Performance Metrics

• Execution Time (Response Time): Time to complete a program or task.
• Throughput (Bandwidth): Number of programs or tasks completed per time unit.
• Execution Time (t_exec, i.e., elapsed time, wall time, real time, response time): Elapsed seconds from start to finish. Includes:
  • Executing instructions
  • Disk access
  • Memory access
  • I/O activities
  • OS overhead
• User CPU Time (t_cpu(user)): Seconds the CPU spends executing the program's instructions.
• System CPU Time (t_cpu(sys)): Seconds the CPU spends executing OS (kernel) instructions